5x^2-20x-960=0

Solution for 5x^2-20x-960=0 equation:

5x^2-20x-960=0

a = 5; b = -20; c = -960;
Δ = b2-4ac
Δ = -202-4·5·(-960)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-140}{2*5}=\frac{-120}{10}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+140}{2*5}=\frac{160}{10}
=16
$